Running persistence

Weekly challenge 238 — 9 October 2023

Week 238: 9 Oct 2023

Task 1

You are given an array of integers. Write a script to return the running sum of the given array. The running sum can be calculated as sum[i] = num[0] + num[1] + …. + num[i].

Example 1Input: @int = (1, 2, 3, 4, 5) Output: (1, 3, 6, 10, 15)Example 2Input: @int = (1, 1, 1, 1, 1) Output: (1, 2, 3, 4, 5)Example 3Input: @int = (0, -1, 1, 2) Output: (0, -1, 0, 2)

There's probably a one-liner for this, but I chose to do it in two. Note that by re-using the input @ints I didn't need to initialise the first member of the output array as it is the same as the input.

#!/usr/bin/perl use v5.16; # The Weekly Challenge - 2023-10-09 use utf8; # Week 237 task 1 - Running sum use strict; # Peter Campbell Smith use warnings; # Blog: http://ccgi.campbellsmiths.force9.co.uk/challenge running_sum(1, 2, 3, 4, 5); running_sum(1, 1, 1, 1, 1); running_sum(0, -1, 1, 2); running_sum(34, 65, 12, -98, 87, 44, 72, 0, 39, 92); sub running_sum { my (@ints, $j, @sums); @ints = @_; say qq[\nInput: \@ints = (], join(', ', @ints) . ')'; for $j (1 .. @ints - 1) { $ints[$j] = $ints[$j - 1] + $ints[$j]; } say qq[Output: (] . join(', ', @ints) . ')'; }

Input: @ints = (1, 2, 3, 4, 5) Output: (1, 3, 6, 10, 15) Input: @ints = (1, 1, 1, 1, 1) Output: (1, 2, 3, 4, 5) Input: @ints = (0, -1, 1, 2) Output: (0, -1, 0, 2) Input: @ints = (34, 65, 12, -98, 87, 44, 72, 0, 39, 92) Output: (34, 99, 111, 13, 100, 144, 216, 216, 255, 347)

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